Math Problems

[Radagast The Brown]

Ok, I have a riddle to you, if someone is still interested...

You need to put 1-12, one number over each line, so that the outcome of every 4 numbers in the... errr... bigger lines, would be equal everywhere.

(this is obviously wrong.)
(I think there's more than one right solution)

Edit - it doesn't work well. .
In entmoot, I guess that if you put blanks it automtically writes it in the side. Never mind...
Anyway, it should be like the sign on my avatar... When each line in made of 4 little lines. and above each you put a number.

[Radagast The Brown]

*sigh*

Ok, the attachment is the shape it should be like:

[Janny]

Okay.
0 divided by 0 equals?
If anything divided by 0 is infinity and anything divided by itself is 1... which of these rules finds its exception in 0/0?

(Sorry RtB, I didn't really understand...)

[Radagast The Brown]

Ok... you see the attachment file in this post? You need to put the numbers, from 1-12, like the picture shows, so that every 4 numbers in line would be equal to the other lines.

[mithrand1r]

Originally posted by Radagast The Brown
Ok... you see the attachment file in this post? You need to put the numbers, from 1-12, like the picture shows, so that every 4 numbers in line would be equal to the other lines.

Here is a soln. that I found using excel and plug n play.


Row 1:-------12
Row 2:-09--05--02--10
Row 3:---06------01
Row 4:-03--04--08--11
Row 5:-------07


Each row totals 26.

Good puzzle Radagast!


post=450

[mithrand1r]

Originally posted by Janny
Okay.
0 divided by 0 equals?
If anything divided by 0 is infinity and anything divided by itself is 1... which of these rules finds its exception in 0/0?

(Sorry RtB, I didn't really understand...)

IIRC, 0/0 is undefined in mathematics.

I am not sure if 0/0 is an exception to any and/or all of the rules you mentioned without opening a mathematics book.

[Radagast The Brown]

Originally posted by mithrand1r
Here is a soln. that I found using excel and plug n play.


Row 1:-------12
Row 2:-09--05--02--10
Row 3:---06------01
Row 4:-03--04--08--11
Row 5:-------07


Each row totals 26.

Good puzzle Radagast!


post=450

Thanks. It's correct, obviously.

[mithrand1r]

Some things that I find interesting with this puzzle.

Notice how the number at the point is equal to the sum of the two number on the far side. (I only show a few numbers, but you could expand this to all 6 point numbers)


Row 1:-------12
Row 2:-09--05--02--10
Row 3:---06------01
Row 4:-03--04--08--11
Row 5:-------07



Row 1:-------12
Row 2:-09--05--02--10
Row 3:---06------01
Row 4:-03--04--08--11
Row 5:-------07



Row 1:-------12
Row 2:-09--05--02--10
Row 3:---06------01
Row 4:-03--04--08--11
Row 5:-------07


Also notice how the triangle point numbers also equal 26.


Row 1:-------12
Row 2:-09--05--02--10
Row 3:---06------01
Row 4:-03--04--08--11
Row 5:-------07



Row 1:-------12
Row 2:-09--05--02--10
Row 3:---06------01
Row 4:-03--04--08--11
Row 5:-------07


I do not know if there is a mathematical reason for this to occur or if this was simply chance, but I still find it interesting.

[Radagast The Brown]

Actually, Mithrandir, my solution was different:

----------11
--10--03--01--12
-----05--------08
--07--09--04--06
----------02

As you can see, it doesn't act like yours.

[Fat middle]

Originally posted by Janny
Okay.
0 divided by 0 equals?
If anything divided by 0 is infinity and anything divided by itself is 1... which of these rules finds its exception in 0/0?

(Sorry RtB, I didn't really understand...)

"Anything divided by 0" is not infinity. I fact, that operation is simply "not defined": you cannot divide by zero.

However if you're studying the limit of something that tends to a real number (zero excepted) divided by something that tends to zero, that limit (if it exists) will always tend to +/- infinity.

That's why people usually say that anything divide by zero is infinity, but it is a very different thing.

[Janny]

Okay, thank you. Here's another:
Complete the blank lines so that each statement is true:

*
The number of 0's in this post is:___
The number of 1's in this post is:___
The number of 2's in this post is:___
The number of 3's in this post is:___
The number of 4's in this post is:___
The number of 5's in this post is:___
The number of 6's in this post is:___
The number of 7's in this post is:___
The number of 8's in this post is:___
The number of 9's in this post is:___
*

The figures which the statement must account for are ALL the figures between the 2 asterisks. eg: The staement 'The number of 1's in this post is: 1' is wrong as it contains two 1's. According to the day school I went to today there is only one solution. They were miffed when I found a second... MWAHAHAHA!

[Radagast The Brown]

The number of 0's in this post is: 1
The number of 1's in this post is: 7
The number of 2's in this post is: 3
The number of 3's in this post is: 2
The number of 4's in this post is: 1
The number of 5's in this post is: 1
The number of 6's in this post is: 1
The number of 7's in this post is: 2
The number of 8's in this post is: 1
The number of 9's in this post is: 1

What about this? It seems right...

[Janny]

Yup. That's the one solution that exists.
Except I got:
0's: 1
1's: 11
2's: 2
3's: 1
4's: 1
5's: 1
6's: 1
7's: 1
8's: 1
9's: 1

The stress of the puzzle was on individual figures, not their actual number.

[Mercutio]

Originally posted by mithrand1r
IIRC, 0/0 is undefined in mathematics.

I am not sure if 0/0 is an exception to any and/or all of the rules you mentioned without opening a mathematics book.

but [an integer other than zero]/[zero]=zero, right?

(3/0=0, 245/0=0, etc.)

[Fat middle]

Originally posted by Mercutio
but [an integer other than zero]/[zero]=zero, right?

(3/0=0, 245/0=0, etc.)

Nope. You deserve a zero

See my post above for [an integer other than zero]/[zero].


But, [zero]/[an integer other than zero] = zero. Though, of course that's completely different...

[Mercutio]

Originally posted by Fat middle
Nope. You deserve a zero

See my post above for [an integer other than zero]/[zero].


But, [zero]/[an integer other than zero] = zero. Though, of course that's completely different...

Ahh...You can have zero threes, but you can't have three zeroes. Gotcha now.

*runs off to cram for math final*

[Janny]

Erm... we're talking about division right?
You can have three zeros and zero threes.
3 x 0 = 0 x 3 = 0

*Runs off to cram for maths GCSE*

[Mercutio]

Originally posted by Janny
Erm... we're talking about division right?
You can have three zeros and zero threes.
3 x 0 = 0 x 3 = 0

*Runs off to cram for maths GCSE*

I was thinking in fractions. For example, 1/5 means you have "one" "fifth."

Maybe I should said you can have "zero" "thirds" but not "three" "zero..eths."

[Beren3000]

Try this logic problem:

All people who live in village A always lie.
All people who live in village B always tell the truth.

You're lost in the woods and you need to find your way to village B. You find an old man in the woods. All you know about him is that he comes from either village A or B. You can only ask him one question. What question would enable you to find the way to village B for sure?

[Mercutio]

Originally posted by Beren3000
Try this logic problem:

All people who live in village A always lie.
All people who live in village B always tell the truth.

You're lost in the woods and you need to find your way to village B. You find an old man in the woods. All you know about him is that he comes from either village A or B. You can only ask him one question. What question would enable you to find the way to village B for sure?

Something like "Which way is your town?"

If he's from A, he'll lie and tell you where B is.

If he's from B, he'll tell the truth and tell you where B is.

Except what if he lied, and told you where neither was. Hmm...