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08-19-2005, 08:45 AM
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#34 |
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Fëanorophobic
Join Date: May 2004
Location: Between the pages of a book
Posts: 1,417
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I didn't get what you did after expanding the log. If you take that "divide by (1-x)" is equivalent to "multiply by (1-x)^-1" Then the expansion works:
(x - 1/2x^2 + 1/3x^3 + ...)/(1-x) =(x - 1/2x^2 + 1/3x^3 + ...) * (1 + x + x^2 + x^3 + ...) = x + x^2 + x^3 - 1/2x^2 -1/2x^3 + 1/3x^3 = x + 1/2x^2 + 5/6x^3 And there's your answer. Last edited by Beren3000 : 08-19-2005 at 08:48 AM. |
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